All points in the box triangle are equal to some continued traction.
Proof:
Given {$T\in\mathcal{C}^+$}, construct a sequence of tractions as follows:
Choose {$F_0$} so that {$T$} is in the range of {$F_0$}. Choose {$F_1$} so that {$F_0^{-1}T$} is in the range of {$F_1$}. Choose {$F_2$} so that {$(F_0F_1)^{-1}T$} is in the range of {$F_2$}.
